(7x+5)(4x^2-19x-5)=0

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Solution for (7x+5)(4x^2-19x-5)=0 equation: 


Simplifying
(7x + 5)(4x2 + -19x + -5) = 0

Reorder the terms:
(5 + 7x)(4x2 + -19x + -5) = 0

Reorder the terms:
(5 + 7x)(-5 + -19x + 4x2) = 0

Multiply (5 + 7x) * (-5 + -19x + 4x2)
(5(-5 + -19x + 4x2) + 7x * (-5 + -19x + 4x2)) = 0
((-5 * 5 + -19x * 5 + 4x2 * 5) + 7x * (-5 + -19x + 4x2)) = 0
((-25 + -95x + 20x2) + 7x * (-5 + -19x + 4x2)) = 0
(-25 + -95x + 20x2 + (-5 * 7x + -19x * 7x + 4x2 * 7x)) = 0
(-25 + -95x + 20x2 + (-35x + -133x2 + 28x3)) = 0

Reorder the terms:
(-25 + -95x + -35x + 20x2 + -133x2 + 28x3) = 0

Combine like terms: -95x + -35x = -130x
(-25 + -130x + 20x2 + -133x2 + 28x3) = 0

Combine like terms: 20x2 + -133x2 = -113x2
(-25 + -130x + -113x2 + 28x3) = 0

Solving
-25 + -130x + -113x2 + 28x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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